How to prepare practicals with mixed concept ( volumetric analysis and dilution

In this type of experiment it has two types of solutions

1. Stock solution (prepared by a teacher or lab technician)   
2. Diluted solution (prepared by a student)

STOCK SOLUTION
stock solutionis sometimes known as a standard solution is a solution which is known it's concentration.

    this stock solution prepared by a subject teacher or lab technician as directed in 24hours instructions.
Stock solution in this experiment has concentration ussualy range 1M-4M for school experimeng and it is volume is very low.

PREPARATION OF STOCK SOLUTION
You as a subject teacher you can decide concentration to be used for your student in learning process

For example you may prepare stock solution with the following concentration.

1. 0.1M of NaOH (Base)
2. 1M of HCl (Acid)

STARTING WITH 0.1M NaOH (Base)
    Click link below to see how 0.1M of NaOH prepared.
👇👇👇
https://kivutiochemistry.blogspot.com/2020/03/preparation-of-chemical-solution-for.html?m=1


FOR ACID (HYDROCHLORIC ACID)
      For a given acid (hydrochloric acid) first you need to know the following;
               1. Percentage of HCl (written on the container of HCl)
               2. Densidy of HCl (written on the container of HCl)
               3. Relative atomic mass of HCl
 Then from the container for hydrochloric acid
            Percentage of hydrochloric acid=36.6%
           Density of hydrochloric acid = 1.18g/L
          Relative atomic mass of hydrochloric acid= 36.5
then calculate concentrated molarity (Mc) of hydrochloric acid by using the following formular
               Mc =(density x percentage x1000) / (Relay atomic mass x100)
                     = 1.18g/L x 36.5 x 1000) / (36.5 x 100)
               Mc  = 11.8M

      Then calculate a concentrated volume that you will be required to extract from container of hydrochloric acid
 this volume can be calculated by using dilution formula

MdVd=McVc

Vc = (MdVd)/Mc
Where;
      Mc is concentrated molarity you calculated it already= 11.8M
      Md is molarity you required to prepare=1M
      Vd is dilluted volume it depend on a number of your students
            For example if you have 20 students you may prepare 4000 cm3
       Vc is concentrated volume you calculate

Now;
           Vc= (1M x 4000cm3) / 11.8M
           Vc= 339cm3

          this is volume will be required to measure from container of concentrated hydrochloric acid then you will dilute it to 4L.

For there already you will be prepare solutions for acid-basetitration.

NB;
During experiment students they will be required to extract maybe 10cm3 or any volume and then they will dillute up to either 50cm3 or 100cm3 it will depend on the instructions.

After extracting maybe 10cm3 and dillute to 100cm3 then concentration of acid will change from 1M to  0.1M( this can be obtained by dillution laws.